MCAT Physical Biological Sciences Practice Test 2

${\displaystyle \mathrm{??}}$is the angle with which a projectile is being thrown from the horizontal x-axisSince, u = 25 m/s, g = 9.8 m/s² and

${\displaystyle \mathrm{??}}$ = 40⁰. Putting the values in the expressin above we get

${\displaystyle t=\frac{2??25??sin40{\displaystyle }}{9.8}}$Or,

${\displaystyle t={3.279}_s}$Option a is the closest to the correct answer and so it is the correct answer option.

$v_x$ is the horizontal velocity;

$v_y$ is the vertical velocitySince horizontal velocity remains constant

$v_x$ = 17 m/s. Vertical velocity is given as

$v_y=v_{yo}???gt$
$v_{yo}$ is the initial velocity;Since, the projectile was thrown at an angle of 60⁰ from x-axis, resolve the initial velocity in two components. One being the horizontal which is constant throughout the flight and the second is the vertical. It is given as 17 sin6⁰ = 14.72 m/s;g is the acceleration due to the gravityt = 2 sTherefore, v_y = 14.72-9.8 x 2Or, v_y = -4.9.Negative sign indicates that body is falling under gravity and the angle to be found is forming below the horizontal as shown.

${\displaystyle tan\mathrm{??}=\left(\frac{???4.9}{17}\right)}$
${\displaystyle Or,\mathrm{??}={\tan }^{???1}???\left(\frac{???4.9}{17}\right)}$ Hence, d is the correct answer option

0.950810 volume = 1.17 x 10^-3m³Since, 1m = 100 cmOr,1m³ = 100³cm³Or, 1m³ = 1000000cm³Or, 1m³ = 10⁶ cm³Hence, converting volume in m³ to cm³ we getvolume = 1.17 x 10^-3 x 10⁶ cm³Hence, e is the correct answer option.

${\displaystyle \frac{g???cm{\displaystyle }}{s}}$Or, 156.7

${\displaystyle \frac{kg???m{\displaystyle }}{s}}$ = 15670000

${\displaystyle \frac{g???cm{\displaystyle }}{s}}$Or, 156.7

${\displaystyle \frac{kg???m{\displaystyle }}{s}}$ = 1.567 x 10 ⁷

${\displaystyle \frac{g???cm{\displaystyle }}{s}}$Hence, c is the correct answer option.

${\displaystyle Pressure=\frac{Force}{Area}}$Dimensional formula of force is MLT^-2 and that of area is L²Pressure =

${\displaystyle \frac{ML{T}^{???2}}{L^2}}$Or, Pressure = ML^-1T^-2Therefore, b is correct.SI unit of volume is m³. Hence, dimensional formula of volume becomes L³ . Therefore, c is correct as well.Power is work done per unit time. Power =

${\displaystyle \frac{work}{time}}$Or, Power =

${\displaystyle \frac{M{L}^2{T}^{???2}}{T}}$Power = ML²T^-3So, e is correct as well.Intensity is given as I =

${\displaystyle \frac{Power}{Area}}$SI unit of intensity is

${\displaystyle \frac{watt}{m^2}}$Or, Intensity =

$\frac{M{L}^2{T}^{???3}}{L^2}$Or, Intensity = MT^-3Hence, d is incorrect and so it is the right answer option.