Common Quantitative Comparison Practice Test 1

By ramefCommon Practice Tests

Question – 1

1. Area of a right triangle is 504 sq.cm. The length of the hypotenuse is 65 cm.?

Column-A Column-B
Sum of the sides containing the right angle Length of the hypotenuse



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:A

  • Answer Explanation:
    The sum of any two sides of a triangle is always greater than the third side. Hence, option A is correct.




Question – 2

2. Consider the sequence -9, -5, -1, 3,….?

Column-A Column-B
The 50th term 191



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:B

  • Answer Explanation:
    Let the first term of the sequence be a and the common difference be d.
    a= -9
    d = -1-(-5) = 5-1=4
    The nth term of the sequence is given byTn=a+(n-1)d
    =-9+(50-1)4
    =-9+49*4
    =-9+196
    =187
    The 50th term is 187
    Option B is correct




Question – 3

3.

Column-A Column-B
Number of ways in which one person can be selected from a group of 10 Number of ways in which two persons can be chosen from a group of 20



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:B

  • Answer Explanation:
    One person can be selected from a group of 10 in C(10,1) ways
    C(10,1)=10!/[1!9!] =10
    Two persons can be selected from a group of 20 in C(20,2) ways
    C(20,2)=20!/[2!18!]
    =20*19/2=10*19=190
    Option B is correct.




Question – 4

4. logx/2=logy/3=logz/5.?

Column-A Column-B
xy yz



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:B

  • Answer Explanation:
    Let logx/2=logy/3=logz/5=k
    logx=2k, logy=3k and logz=5k
    logx+logy = 2k+3k=5k
    log(xy) = 5klogy+logz = 3k+5k=8k
    log(yz) = 8k

    log(xy)




Question – 5

5. The average of the marks obtained by 30 students of a class is 50. If the score of one student is removed, the average reduces by 1.?

Column-A Column-B
Average score of the remaining students The score that was removed



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:B

  • Answer Explanation:
    Average = Total marks/number of students
    Total marks = Average*number of students
    = 50*30 = 1500New average = 50-1=49
    Number of students = 30-1=29
    Total marks = 49*29
    = 1421
    Marks of the student = 1500-1421
    = 79
    The score that was removed = 79
    Average score of the remaining students = 49
    Option B is correct.




Question – 6

6. A square is constructed taking a side of a rectangle as a side of the square.?

Column-A Column-B
Perimeter of the square Perimeter of the rectangle



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:D

  • Answer Explanation:
    We do not know whether the square is along the length or along the breath of the rectangle.
    Hence, we cannot compare the perimeters.
    Option D is correct.




Question – 7

7. A point divides the line joining (-1,-5) and (6,5) in the ratio 1:6.?

Column-A Column-B
Ordinate of the point Abscissa of the point



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:B

  • Answer Explanation:
    The coordinates of the point are given by
    ((-1*6+6*1)/(6+1), (-5*6+5*1)/(6+1))
    = ((-6+6)/7, (-30+5)/7)
    = (0, -25/7)
    Abscissa is the x co-ordinate and hence it is greater than the ordinate, which is the y co-ordinate.
    Option B is correct.




Question – 8

8.

Column-A Column-B
Number of two-digit numbers Number of three-digit numbers less than 250



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:B

  • Answer Explanation:
    Number of two-digit numbers = 99-9=90
    Number of three-digit numbers less than 250=250-99=151
    90<151
    Option B is correct.




Question – 9

9.

Column-A Column-B
Number of vertices of a rectangle Number of triangles that can be formed from the vertices of a rectangle



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:C

  • Answer Explanation:
    Number of vertices of a rectangle = 4
    Number of triangles that can be formed from the vertices of a rectangle = C(4,3)
    = 4!/(3!1!)
    = 4
    Hence, option C is correct.




Question – 10

10.

Column-A Column-B
Perimeter of a square with each side 29 cm long. Perimeter of a rhombus whose diagonals are 40cm and 42cm long



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:C

  • Answer Explanation:
    Perimeter of the square = 29*4=116 cm
    The diagonals of a rhombus bisect each other at right angles.
    Thus, the rhombus is divided into 4 congruent right triangles.
    The hypotenuse of any triangle is a side of the rhombus.
    Applying Pythagoras theorem, we get
    Hypotenuse = Sqrt[(40/2)^2+(42/2)^2]
    = sqrt(20^2+21^2)
    = sqrt(400+441)
    = sqrt(841)
    = 29cm
    Perimeter of the rhombus = 4*29
    = 116 cmOption C is correct.
    [20^2=20*20]




Question – 11

11. The radius of a circle is 49cm. Each side of a square is equal to the diameter of the circle.?

Column-A Column-B
Area of the square Area of the circle



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:A

  • Answer Explanation:
    Area of the circle = pi*r^2, where r is the radius of the circle
    Area = 22/7*49*49=7546 sq.cm.Each side of the square = 2*radius
    = 2*49 = 98cm
    Area of square = side*side
    = 98*98
    =9604 sq.cm.

    Option A is correct.
    [pi=22/7, r^2=r*r]




Question – 12

12. A chord of length 112 cm is at a distance of 33 cm from the centre. ?

Column-A Column-B
Length of the chord. Radius of the circle



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:A

  • Answer Explanation:
    A line drawn from the center of the circle perpendicular to the chord will bisect the chord.
    This line, the radius of the circle and the chord form a right triangle.
    Applying the Pythagoras theorem to the triangle, we get
    Hypotenuse = sqrt[base^2+perpendicular^2]
    = sqrt[(112/2)^2+33^2]
    = sqrt[56^2+1089]
    = sqrt[3136+1089]
    = sqrt(4225) = 65cm
    Radius of the circle is 65 cm.
    Length of the chord is 112 cm.
    Option A is correct.
    [x^2=x*x]




Question – 13

13. The population of a town is 140000. It increases by 5% in the first year. In the second year, it decreases by 10%.?

Column-A Column-B
Population after the first year Population after the second year



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:A

  • Answer Explanation:
    This problem is similar to a problem of compound interest.
    Population after 1 year = 140000(1+5/100) = 147000
    Population after 2 years = 147000(1-10/100) = 132300
    Option A is correct.




Question – 14

14.

Column-A Column-B
Number of factors of 20 that are smaller than 40 Number of multiples of 20 that are smaller than 45



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:A

  • Answer Explanation:
    Factors of 20 = 1, 2, 4, 5, 10, 20
    Multiples of 20 that are smaller than 45 = 20, 40
    Option A is correct.




Question – 15

15. A teacher prepares a test having 5 objective-type questions. Each question has an incorrect and a correct option.?

Column-A Column-B
The number of correct ways in which the test can be answered The number of incorrect ways in which the test can be answered



  • A. If the quantity on the left is greater


  • B. If the quantity on the right is greater


  • C. If both are equal


  • D. If the relationship cannot be determined without further information


  • Answer:B

  • Answer Explanation:
    Each question can be answered in 2 ways
    There are in all 5 questions.
    Number of ways in which the test can be answered = 2*2*2*2*2 = 32
    Number of correct ways of answering the test = 1
    Number of incorrect ways of answering the test = 32-1=31
    Option B is correct.




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